2 solutions

  • 1
    @ 2026-1-10 15:06:36
    #include<stdio.h>
    int main()
    {
        int a;
        scanf("%d",&a);
        
        if((a%4==0&&a%100!=0)||(a%400==0))
        printf("Y");
        else
        printf("N");
        
        return 0;
    }
    
    • 0
      @ 2024-7-28 17:20:08
      #include<iostream>
      using namespace std;
      int main()
      {
          int n;
          cin>>n;
          if((n % 4 == 0 && n % 100 != 0) || (n / 100 == 0 || n % 400 == 0)){
              cout<<"Y"<<endl;
          }
          else cout<<"N"<<endl;
          return 0;
      }
      
      • 1

      Information

      ID
      6733
      Time
      1000ms
      Memory
      128MiB
      Difficulty
      6
      Tags
      (None)
      # Submissions
      290
      Accepted
      97
      Uploaded By