直接暴力，不需要分类讨论

#include<stdio.h> int main(){ int a,b,c,x,y; int flag = 0; scanf("%d %d %d",&a,&b,&c); for(x=0; x<=10000; x++){ for(y=0; y<=10000; y++){ if(ax+by+c == 0){ flag++; } } } printf("%d",flag); }

用一手floor函数

#include<bits/stdc++.h>
using namespace std;
int main(){
	int a,b,c;
	scanf("%d %d %d",&a,&b,&c); 
	double x;
	int flag=0;
	for(int y=0;y<10001;y++){
		x=(-b*(double)y-c)/a;
		if(x>=0&&x<=10000&&floor(x+0.5)==x){
			flag++;
		}
	}
	cout<<flag;
	return 0;
}

#include <stdio.h>

int main() { int count=0,a, b, c, x, y; scanf("%d %d %d", &a, &b, &c); for(x=0;x<=10000;x++) { for(y=0;y<=10000;y++) { if((ax+by+c)==0){count++;} } } printf("%d", count); return 0; }

我的评价是，直接枚举。

#include <bits/stdc++.h>
using namespace std;
#define ll long long


int main()
{
	int a,b,c;
	cin>>a>>b>>c;
	int ans=0;
	for(int i = 0; i <= 10000; i++){
		for(int j = 0; j <= 10000; j++){
			if(a*i+b*j+c == 0)	ans++;
		}
	}
	cout << ans << endl; 
  	return 0;
}

小白写法，分类讨论

#include <stdio.h>
int main() {
	long long  a, b, c, sum = 0, sum2 = 0, temp=0;
	scanf("%lld %lld %lld", &a, &b, &c);
	if (b != 0) {
		for (int y = 0; y <= 10000; y++) {
			for (int x = 0; x <= 10000; x++) {
				if (y == -(c + a * x)*1.0/ b) sum += 1;
			}
		}
	}else if (a * c > 0) sum = 0;
	else if (a==0&&c==0) sum = 10001 * 10001;
	else if (a==0&&c!=0) sum =0;
	else if (a*c < 0) sum = 10001;
	printf("%lld\n", sum);
	return 0;
}