1 solutions
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0
#include<bits/stdc++.h> using namespace std; using ll = long long; const int N = 1e5+10; int a[N],sum; int main() { int n;cin>>n; int maxx = -10001,minn = 10001; for(int i = 1;i <= n;i++) { cin>>a[i]; } for(int i = 1;i <= n;i++) { sum += a[i]; maxx = max(maxx,a[i]); minn = min(minn,a[i]); } cout<<maxx<<"\n"<<minn<<"\n"<< sum<<"\n"; return 0; }
- 1
Information
- ID
- 1832
- Time
- 1000ms
- Memory
- 512MiB
- Difficulty
- 4
- Tags
- # Submissions
- 42
- Accepted
- 19
- Uploaded By