1 solutions

  • 0
    @ 2024-10-21 22:39:24

    #include <stdio.h> int main() { int n,m,k,t,i,j,x,y; scanf("%d %d %d",&n,&m,&k); int a[n][m]; int b[m][k]; int sum=0; for( i=0;i<n;i++){ for(j=0;j<m;j++){ scanf("%d",&a[i][j]); } } for(i=0;i<m;i++){ for(j=0;j<k;j++){ scanf("%d",&b[i][j]); } } int c[n][k]; j=0; i=0; while(i!=n&&j!=k){ x=i; y=j; sum=0; for(t=0;t<m;t++){ sum=sum+a[x][t]*b[t][y]; } c[i][j]=sum; j++; if(j==k){ j=0; i++; } } for(i=0;i<n;i++){ for(j=0;j<k;j++){ printf("%d ",c[i][j]); } printf("\n"); } return 0; }

    • 1

    Information

    ID
    6783
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    7
    Tags
    (None)
    # Submissions
    155
    Accepted
    30
    Uploaded By