3 solutions

  • 0
    @ 2025-11-2 18:15:24

    #include<stdio.h>

    #include<math.h>

    int main(){

    int n=0,a=0;

    scanf("%d",&n);

    if(n>0){

    while(n>0&&n%10==0){

    n/=10;}

    while(n>0){

    a=n%10;

    printf("%d",a);

    n/=10;

    }

    }else if(n<0){

    int c=abs(n);

    printf("-");

    while(c>0&&c%10==0){

    c/=10;}

    while(c>0){

    a=c%10;

    printf("%d",a);

    c/=10;}

    }else{printf("0");

    }

    return 0;

    }

    • 0
      @ 2023-10-25 15:46:01
      #include<stdio.h>
      #include<math.h>
      #pragma warning(disable:4996) 
      int main()
      {
          int num,temp=0;
          scanf("%d",&num);
          do
          {
              temp = temp * 10 + num % 10;
              num /= 10;
          } while (num);
          printf("%d", temp);
          return 0;
      }
      
      • 0
        @ 2023-10-1 13:31:18
        #include<iostream>
        using namespace std;
        int main()
        {
            cin >> n;
        	if (n<0)
        	{
        		cout << "-";
        		n = -n;
        	}
        	for (; n; n/=10)
        	{
        		ans = n % 10 + ans * 10;
        		//cout << ans<<' ';
        	}
        	cout << ans;
        	return 0;
        }
        
        • 1

        Information

        ID
        6755
        Time
        1000ms
        Memory
        128MiB
        Difficulty
        8
        Tags
        (None)
        # Submissions
        412
        Accepted
        79
        Uploaded By