#include <stdio.h>
#include <math.h>
int main()
{
	double a,b,c;
	scanf("%lf %lf %lf",&a,&b,&c);
	double t=b*b-4*a*c;
	double x1=(-b+sqrt(t))/(2*a);
	double x2=(-b-sqrt(t))/(2*a);
	while(t>=0){
		if(t==0)
			printf("x1=x2=%.5f",x1);
		else//t>0
		{
			if(x1<x2)
				printf("x1=%.5f;x2=%.5f",x1,x2);
			else//x2<x1
				printf("x1=%.5f;x2=%.5f",x2,x1);
		}
		return 0;
	}	
	printf("No answer!");
	return 0;
}

#include<iostream>
#include<cmath>
using namespace std;
int main()
{
    double a,b,c,x1,x2;
    scanf("%lf %lf %lf",&a,&b,&c);
    x1 = (-b + sqrt(b * b - 4 * a * c)) / (2 * a);
    x2 = (-b - sqrt(b * b - 4 * a * c)) / (2 * a);
    double res = b * b - 4 * a * c;
    if(res < 0){
        printf("No answer!");
    }else 
        if(res == 0){
            printf("x1=x2=%.5lf",x1);
        }else
            if(res > 0){
                if(x1 > x2){
                    swap(x1,x2);
                }
                printf("x1=%.5lf;x2=%.5lf",x1,x2);
            }else printf("No answer!");
    return 0;
}

#include <stdio.h>
#include <math.h> //要用到开平方和平方
int main()
{
    double a, b, c;
    scanf("%lf %lf %lf", &a, &b, &c);/*现在只能说是一元二次型方程， 因为a的值未知*/
    double d = pow(b, 2) - 4 * a * c; /*d就是那个德尔塔但是没开根号*/
    if (d < 0 || a == 0) /*如果a等于零那么就是一元一次方程*/
    {
        printf("No answer!");
    }
    else if (d >= 0)
    {
        double x1 = (0 - b + sqrt(d)) / (2 * a);
        double x2 = (0 - b - sqrt(d)) / (2 * a);
        if (x1 < x2)
        {
            printf("x1=%.5f;x2=%.5f", x1, x2);
        }
        else if (x1 > x2)
        {
            printf("x1=%.5f;x2=%.5f", x2, x1);
        }
        else if (x1 == x2)
        {
            printf("x1=x2=%.5f", x1);
        }
    }
    return 0;
}

#include <stdio.h>
#include <math.h>
int main()
{
    double a,b,c,d,x1,x2,max,min;
    scanf("%lf %lf %lf",&a,&b,&c);
    d=b*b-4*a*c;x1=(-b+sqrt(d))/(2*a);x2=(-b-sqrt(d))/(2*a);
    if(x1==x2){printf("x1=x2=%.5f",x1);}else{
    if(x1<x2){max=x2;min=x1;}else{max=x1;min=x2;};
    if(d<0){printf("No answer!");};
    if(d>0){printf("x1=%.5f;x2=%.5f",min,max);};}
    return 0;
}

#include<math.h>
int main()
{
    double a,b,c,d,x1,x2,e;
    scanf("%lf %lf %lf",&a,&b,&c);
    d=b*b-4*a*c;
    if(d<0){
        printf("No answer!");
    }else{
        if(d==0){
            x1=x2=(-b)/(2*a);
            printf("x1=x2=%.5f",x1);
        }else{
            e=sqrt(d);
            x1=(-b+e)/(2*a);
            x2=(-b-e)/(2*a);
           if(x1<x2){
            printf("x1=%.5f;x2=%.5f",x1,x2);
            }else{
                printf("x1=%.5f;x2=%.5f",x2,x1);
                }
        }
    }return 0;
}