Problem Solution - 带余除法

李红阳 LV 10 @ 2023-9-30 13:45:27

#include<iostream>
using namespace std;
#define ll long long
ll a,b,c;
int main()
{
	cin>>a>>b;
	c=a/b;
	cout<<c<<" "<<(a-b*c);
	return 0;
}

1 solutions