1 solutions
-
0
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
int x,k,c;
ll m; bool f(int x, ll m, int k, int c) {
ll y=0; for (int i = 0; i < m; i++) { y+=((x%k)*((ll)pow(10,i)%k))%k; } if (y == c) return true; else return false;
}
int main() {
cin >> x >> m >> k >> c; if (f(x, m, k, c))cout << "Yes" << endl; else cout << "No" << endl; return 0;
}
- 1
Information
- ID
- 1552
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 5
- Tags
- (None)
- # Submissions
- 18
- Accepted
- 14
- Uploaded By