2 solutions

  • 0
    @ 2022-2-24 9:15:04
    #include<bits/stdc++.h>
    using namespace std;
    int main(){
    	long long a,b;
    	while(cin>>a>>b){
    		long long t;
    		while(b>0){
    			t=a%b;
    			a=b;
    			b=t;
    		}
    		cout<<a<<endl;
    	}
    	return 0;
    }
    • -1
      @ 2022-3-2 23:21:06

      `

      #include<bits/stdc++.h>
      using namespace std;
      typedef long long ll;
      const int N=1e6+19;
      ll a[N];
      int main()
      {
      	ll a,b,ans;
      	while(cin>>a>>b)
      	{
      		ans=__gcd(a,b);
      		cout<<ans<<"\n";
      	}
      	
      	return 0;
      }
      
      • 1

      Information

      ID
      286
      Time
      1000ms
      Memory
      256MiB
      Difficulty
      3
      Tags
      # Submissions
      94
      Accepted
      48
      Uploaded By