1 solutions
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0
#include<bits/stdc++.h> using namespace std; int main() { int i,j,n,m,t1,t2,t1i,t1j,t2i,t2j,a[205][205]; cin >> n >> m; for(i = 1; i <= n; i++){ for(j = 1; j <= m; j++){ cin >> a[i][j]; } } cin >> t1 >> t2; for(i = 1; i <= n; i++){ for(j = 1; j <= m; j++){ if(a[i][j] == t1){ t1i = i; t1j = j; } if(a[i][j] == t2){ t2i = i; t2j = j; } } } if((t1i-t2i == -1 || t1i-t2i == 1)&&(t1j-t2j == 0)||(t1j-t2j == -1||t1j-t2j == 1)&&(t1i-t2i == 0)){ cout << "Y" << endl; }else{ cout << "N" << endl; } return 0; }
- 1
Information
- ID
- 1337
- Time
- 1000ms
- Memory
- 64MiB
- Difficulty
- 10
- Tags
- # Submissions
- 1
- Accepted
- 1
- Uploaded By