1 solutions

  • 0
    @ 2022-2-13 22:38:36
    #include<bits/stdc++.h>
    using namespace std;
    #define ll long long
    ll n,m,l,r,ans=0;
    const ll N=1e8+5;
    ll a[N],b[N];
    ll find(ll g){
    	l=1,r=n;
    	while(l<=r){
    		ll mid=(l+r)/2;
    		if(a[mid]>=g){
    			r=mid-1;
    		}
    		else{
    			l=mid+1;
    		}
    	}
    	return l;
    }
    int main(){
    	cin>>n>>m;
    	for(ll i=1;i<=n;i++){
    		cin>>a[i];
    	}
    	sort(a+1,a+n+1);
    	for(ll i=1;i<=m;i++){
    		cin>>b[i];
    		if(b[i]<=a[1]){
    			ans+=a[1]-b[i];
    		}
    		else{
    			ans+=min(abs(a[find(b[i])]-b[i]),abs(a[find(b[i])-1]-b[i]));
    		}
    	}
    	cout<<ans;
    	return 0;
    }
    • 1

    Information

    ID
    1235
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    6
    Tags
    # Submissions
    76
    Accepted
    23
    Uploaded By