1 solutions
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#include <iostream> #include <cmath> #include <algorithm> #define QAQ ios::sync_with_stdio(false),cin.tie(0),cout.tie(0); const int N=100005; using namespace std; int n,h[N],dp1[N],cnt=0;//dp1记录最后一个上升的数,cnt记录数量 int find(int l,int r,int x)//用二分查找从左找到dp1中第一个大于x的数 { while(l<r) { int mid=(l+r)/2; if(dp1[mid]>=x) r=mid; else l=mid+1; } return l; } int main(){ QAQ; //求最长上升子序列 cin>>n; dp1[0]=-1e9; for(int i=1;i<=n;i++) { cin>>h[i]; if(h[i]>dp1[cnt])//如果上升,则记录dp1; { dp1[++cnt]=h[i]; // cout<<cnt<<' '; } else { int j=find(1,cnt,h[i]); dp1[j]=h[i]; // cout<<j<<'|'; } } cout<<cnt; return 0; }
- 1
Information
- ID
- 1229
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 8
- Tags
- # Submissions
- 27
- Accepted
- 5
- Uploaded By