1 solutions
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0
#include<bits/stdc++.h> using namespace std; int a[110]; int main() { int n, ma = 0, g = 0; cin >> n; for (int i = 0; i < n; i++){ cin >> a[i]; if(a[i] > a[ma]) a[ma] = a[i]; } for(int i = 0; i < n; i++) if(a[i] == a[ma]) g++; sort(a,a+n,greater<int>());//内置类型的由大到小排序 for(int i = 0; i < n; i++){ cout << a[i+g]; break; } return 0; }
- 1
Information
- ID
- 1148
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- 10
- Tags
- # Submissions
- 4
- Accepted
- 2
- Uploaded By