1 solutions
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0
就直接模拟输出注意对齐和空格
#include<bits/stdc++.h> typedef long long LL; using namespace std; int main () { int n,n1,n2; char c = '*'; cin >> n; n1 = (n + 1) / 2; n2 = n / 2; for(int i = 1;i <= n1;++ i)//上层 { for(int j = 1;j < i;++ j) { cout << " ";//打印空格 } for(int j = 1;j <= (n1 - i) * 2 + 1;++ j) { cout << c; } cout << "\n"; } for(int i = 1;i <= n2;++ i)//下层 { for (int j = 1; j < n2 - i + 1;++ j) cout << " "; for (int j = 1; j <= 2 * i + 1; j++) cout << c; cout << "\n"; } return 0; }
- 1
Information
- ID
- 414
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- 5
- Tags
- # Submissions
- 84
- Accepted
- 35
- Uploaded By