2 solutions

  • 0
    @ 2023-11-27 20:35:32
    #include <bits/stdc++.h>
    using namespace std;
    signed main(void)
    {
    	std::ios::sync\_with\_stdio(false);
    	std::cin.tie(0);
    	int x,y;
    	for ( x =1;x<80+1;x++)
    	{	
    		for ( y=1;y<40+1;y++)
    		{
    		if ((x+y==50)&&(x\*2+y\*4==160))
    		{
    			cout<<x<<" "<<y;
    		}
    		}
    	}
    	return 0;
    }
    
    • 0
      @ 2023-10-21 12:47:54
      #include <stdio.h>
      int main()
      {
          int x,y;
          int k=50;
          int sum=160;
          int j;
          for(x=1;x<=k;x++)
          {
              y=k-x;
              if(2*x+4*y==sum)
                  {
                      printf("%d %d",x,y);
                      j=1;
                      break;
                  }
             if(j==1)
             break;
          }
          return 0;
      }
      
      • 1

      Information

      ID
      347
      Time
      1000ms
      Memory
      16MiB
      Difficulty
      3
      Tags
      # Submissions
      147
      Accepted
      76
      Uploaded By