2 solutions

  • 0
    @ 2025-1-29 20:28:16

    #include<bits/stdc++.h> using namespace std; const int N=1e2+10; char a[N][N]; bool check[N][N]; int m,n,tx,ty; struct point{ int x; int y; int step; }; int dx[4]={0,-1,0,1}; int dy[4]={-1,0,1,0}; queueq; void bfs() { check[tx][ty]=true; point temp; temp.x=tx; temp.y=ty; temp.step=0; q.push(temp); while(!q.empty()){ if(a[q.front().x][q.front().y]'T'){ cout<<q.front().step; break; } for(int i=0;i<4;i++){ int nx=dx[i]+q.front().x; int ny=dy[i]+q.front().y; if(a[nx][ny]!='#'&&!check[nx][ny]&&nx>=0&&nx<n&&ny>=0&&ny<m){ check[nx][ny]=true; temp.x=nx; temp.y=ny; temp.step=q.front().step+1; q.push(temp); } } q.pop(); } } int main() { cin>>n>>m; int i,j; for(i=0;i<n;i++){ for(j=0;j<m;j++){ cin>>a[i][j]; if(a[i][j]'S'){ tx=i; ty=j; } } } bfs(); return 0; }

    • 0
      @ 2022-3-25 14:35:59
      #include <stdio.h>
      #include <math.h>
      #include <algorithm>
      #include <iostream>
      #include <string.h>
      #include <queue>
      #include <stack>
      #include <map>
      #include <set>
      #include <vector>
      using namespace std;
      int n,m;
      int dx[4]= {0,0,1,-1},dy[4]= {1,-1,0,0};
      struct temp {
          int x,y,step;
      };
      queue<temp> q;
      char a[105][105];
      int vis[105][105];
      void bfs(int xx,int yy) {
          while(!q.empty()) {
              temp k=q.front();
              if(a[k.x][k.y]=='T') {
                  cout<<k.step<<endl;
                  return ;
              }
              q.pop();
              if(vis[k.x][k.y])
                  continue;
                  vis[k.x][k.y]=1;
              for(int i=0; i<4; i++) {
                  int tx=k.x+dx[i],ty=k.y+dy[i];
                  if(tx>=0&&ty>=0&&tx<n&&ty<m&&!vis[tx][ty]&&a[tx][ty]!='#') {
                      q.push({tx,ty,k.step+1});
                  }
              }
          }
      }
      int main() {
          scanf("%d%d",&n,&m);
          for(int i=0; i<n; i++) {
              cin>>a[i];
          }
          for(int i=0; i<n; i++) {
              for(int j=0; j<m; j++) {
                  if(a[i][j]=='S') {
                      q.push({i,j,0});
                      bfs(i,j);
                      return 0;
                  }
              }
          }
          return 0;
      }
      
      • 1

      Information

      ID
      770
      Time
      1000ms
      Memory
      128MiB
      Difficulty
      6
      Tags
      # Submissions
      191
      Accepted
      53
      Uploaded By