1 solutions

  • 0
    @ 2023-1-17 15:06:16
    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
    	int n, s = 0; //周长
    	cin >> n;
    	//遍历一条边可能的范围
    	for(int i = 1; i <= n/2-1; i++){
    		//记录最大的面积
    		if(i*(n/2-i) > s){
    			s = i*(n/2-i);
    		} 
    	} 
    	cout << s << endl;
    	return 0;
    }
    
    
    • 1

    Information

    ID
    693
    Time
    1000ms
    Memory
    16MiB
    Difficulty
    10
    Tags
    # Submissions
    2
    Accepted
    1
    Uploaded By