1 solutions
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#include<bits/stdc++.h> using namespace std; int main() { int i,j,k,l;//分别代表4个人的年龄 //遍历第一个人年龄可能的范围 for(i = 1; i <= 23; i++){ //遍历第二个人年龄可能的范围 for(j = i+1; j <= 26-i-2; j++){ k = j + j - i;//第三个人年龄 l = k + j - i;//第四个人年龄 //总年龄26,且乘积880则输出 if(i+j+k+l == 26 && i*j*k*l == 880){ cout << i << " " << j << " " << k << " " << l << endl; } } } return 0; }
- 1
Information
- ID
- 591
- Time
- 1000ms
- Memory
- 16MiB
- Difficulty
- 10
- Tags
- # Submissions
- 3
- Accepted
- 3
- Uploaded By