5 solutions

  • 0
    @ 2023-11-17 16:34:53
    #include <stdio.h>
    #include <math.h> //要用到开平方和平方
    int main()
    {
        double a, b, c;
        scanf("%lf %lf %lf", &a, &b, &c);/*现在只能说是一元二次型方程, 因为a的值未知*/
        double d = pow(b, 2) - 4 * a * c; /*d就是那个德尔塔但是没开根号*/
        if (d < 0 || a == 0) /*如果a等于零那么就是一元一次方程*/
        {
            printf("No answer!");
        }
        else if (d >= 0)
        {
            double x1 = (0 - b + sqrt(d)) / (2 * a);
            double x2 = (0 - b - sqrt(d)) / (2 * a);
            if (x1 < x2)
            {
                printf("x1=%.5f;x2=%.5f", x1, x2);
            }
            else if (x1 > x2)
            {
                printf("x1=%.5f;x2=%.5f", x2, x1);
            }
            else if (x1 == x2)
            {
                printf("x1=x2=%.5f", x1);
            }
        }
        return 0;
    }
    

    Information

    ID
    6735
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    9
    Tags
    (None)
    # Submissions
    717
    Accepted
    73
    Uploaded By