4 solutions

  • 1
    @ 2023-9-30 20:02:29
    #include <stdio.h>
    #include <math.h>
    int main()
    {
    	double a,b,c;
    	scanf("%lf %lf %lf",&a,&b,&c);
    	double t=b*b-4*a*c;
    	double x1=(-b+sqrt(t))/(2*a);
    	double x2=(-b-sqrt(t))/(2*a);
    	while(t>=0){
    		if(t==0)
    			printf("x1=x2=%.5f",x1);
    		else//t>0
    		{
    			if(x1<x2)
    				printf("x1=%.5f;x2=%.5f",x1,x2);
    			else//x2<x1
    				printf("x1=%.5f;x2=%.5f",x2,x1);
    		}
    		return 0;
    	}	
    	printf("No answer!");
    	return 0;
    }
    

    Information

    ID
    6735
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    9
    Tags
    (None)
    # Submissions
    549
    Accepted
    48
    Uploaded By