1 solutions
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#include <cstring> #include <iostream> #include <algorithm> using namespace std; const int N = 300010, INF = 0x3f3f3f3f; int n, m; int s[N], q[N]; int main() { scanf("%d%d", &n, &m); for (int i = 1; i <= n; i ++ ) { scanf("%d", &s[i]); s[i] += s[i - 1]; } int res = -INF; int hh = 0, tt = 0; for (int i = 1; i <= n; i ++ ) { if (q[hh] < i - m) hh ++ ; res = max(res, s[i] - s[q[hh]]); while (hh <= tt && s[q[tt]] >= s[i]) tt -- ; q[ ++ tt] = i; } printf("%d\n", res); return 0; }
- 1
Information
- ID
- 6695
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 8
- Tags
- # Submissions
- 80
- Accepted
- 4
- Uploaded By