2 solutions

  • 0
    @ 2025-2-24 16:11:54

    #include using namespace std; int dp[105][20005]; int main(){ int maxw, n; cin >> maxw >> n; //处理dp边界值 //0件物品时,n=0 for(int i = 0; i <= maxw; i++){ dp[0][i] = 0; } //0的重量 for(int j = 0; j <= n; j++){ dp[j][0] = 0; }

    //n件物品 
    for(int i = 1; i <= n; i++){
    	int w, p;
    	cin >> w >> p;
    	for(int j = 1; j <= maxw; j++){
    		if(j < w) dp[i][j] = dp[i - 1][j];
    		else dp[i][j] = max(dp[i -1][j], dp[i - 1][j - w] + p);
    	}
    }
    cout << dp[n][maxw];
    return 0;
    

    }

    Information

    ID
    620
    Time
    1000ms
    Memory
    64MiB
    Difficulty
    8
    Tags
    # Submissions
    113
    Accepted
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