3 solutions
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1
龟速乘
#include <bits/stdc++.h> using namespace std; int main(){ int n; long long c,sum = 0; cin>>n>>c; long long a[n]; for(int i = 0 ; i < n ; i++){ cin>>a[i]; a[i] %= c; } for(int i = 1 ; i < n ; i++){ while(a[i] > 0){ if(a[i] & 1){ sum = (sum % c + a[0] % c) % c; } a[0] = (a[0] % c + a[0] % c) % c; a[i] = a[i] / 2; } a[0] = sum; sum = 0; } cout<<a[0]<<endl; return 0; }
Information
- ID
- 1549
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 6
- Tags
- # Submissions
- 150
- Accepted
- 43
- Uploaded By