3 solutions

  • 1
    @ 2022-4-1 17:39:15

    龟速乘

    #include <bits/stdc++.h>
    using namespace std;
    int main(){
        int n;
        long long c,sum = 0;
        cin>>n>>c;
        long long a[n];
        for(int i = 0 ; i < n ; i++){
            cin>>a[i];
            a[i] %= c;
        }
        for(int i = 1 ; i < n ; i++){
            while(a[i] > 0){
                if(a[i] & 1){
                    sum = (sum % c + a[0] % c) % c;
                }
                a[0] = (a[0] % c + a[0] % c) % c;
                a[i] = a[i] / 2;
            }
            a[0] = sum;
            sum = 0;
        }
        cout<<a[0]<<endl;
        return 0;
    }
    

    Information

    ID
    1549
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    6
    Tags
    # Submissions
    150
    Accepted
    43
    Uploaded By