#P235E. Number Challenge

    ID: 2519 Type: RemoteJudge 3000ms 512MiB Tried: 0 Accepted: 0 Difficulty: (None) Uploaded By: Tags>combinatoricsdpimplementationmathnumber theory*2600

Number Challenge

No submission language available for this problem.

Description

Let's denote d(n) as the number of divisors of a positive integer n. You are given three integers a, b and c. Your task is to calculate the following sum:

Find the sum modulo 1073741824 (230).

The first line contains three space-separated integers a, b and c (1 ≤ a, b, c ≤ 2000).

Print a single integer — the required sum modulo 1073741824 (230).

Input

The first line contains three space-separated integers a, b and c (1 ≤ a, b, c ≤ 2000).

Output

Print a single integer — the required sum modulo 1073741824 (230).

Samples

2 2 2

20

4 4 4

328

10 10 10

11536

Note

For the first example.

  • d(1·1·1) = d(1) = 1;
  • d(1·1·2) = d(2) = 2;
  • d(1·2·1) = d(2) = 2;
  • d(1·2·2) = d(4) = 3;
  • d(2·1·1) = d(2) = 2;
  • d(2·1·2) = d(4) = 3;
  • d(2·2·1) = d(4) = 3;
  • d(2·2·2) = d(8) = 4.

So the result is 1 + 2 + 2 + 3 + 2 + 3 + 3 + 4 = 20.