#P1623D. Robot Cleaner Revisit

    ID: 6248 Type: RemoteJudge 3000ms 256MiB Tried: 0 Accepted: 0 Difficulty: (None) Uploaded By: Tags>implementationmathprobabilities*2300

Robot Cleaner Revisit

No submission language available for this problem.

Description

The statement of this problem shares a lot with problem A. The differences are that in this problem, the probability is introduced, and the constraint is different.

A robot cleaner is placed on the floor of a rectangle room, surrounded by walls. The floor consists of nn rows and mm columns. The rows of the floor are numbered from 11 to nn from top to bottom, and columns of the floor are numbered from 11 to mm from left to right. The cell on the intersection of the rr-th row and the cc-th column is denoted as (r,c)(r,c). The initial position of the robot is (rb,cb)(r_b, c_b).

In one second, the robot moves by drdr rows and dcdc columns, that is, after one second, the robot moves from the cell (r,c)(r, c) to (r+dr,c+dc)(r + dr, c + dc). Initially dr=1dr = 1, dc=1dc = 1. If there is a vertical wall (the left or the right walls) in the movement direction, dcdc is reflected before the movement, so the new value of dcdc is dc-dc. And if there is a horizontal wall (the upper or lower walls), drdr is reflected before the movement, so the new value of drdr is dr-dr.

Each second (including the moment before the robot starts moving), the robot cleans every cell lying in the same row or the same column as its position. There is only one dirty cell at (rd,cd)(r_d, c_d). The job of the robot is to clean that dirty cell.

After a lot of testings in problem A, the robot is now broken. It cleans the floor as described above, but at each second the cleaning operation is performed with probability p100\frac p {100} only, and not performed with probability 1p1001 - \frac p {100}. The cleaning or not cleaning outcomes are independent each second.

Given the floor size nn and mm, the robot's initial position (rb,cb)(r_b, c_b) and the dirty cell's position (rd,cd)(r_d, c_d), find the expected time for the robot to do its job.

It can be shown that the answer can be expressed as an irreducible fraction xy\frac x y, where xx and yy are integers and y≢0(mod109+7)y \not \equiv 0 \pmod{10^9 + 7} . Output the integer equal to xy1mod(109+7)x \cdot y^{-1} \bmod (10^9 + 7). In other words, output such an integer aa that 0a<109+70 \le a < 10^9 + 7 and ayx(mod109+7)a \cdot y \equiv x \pmod {10^9 + 7}.

Each test contains multiple test cases. The first line contains the number of test cases tt (1t101 \le t \le 10). Description of the test cases follows.

A test case consists of only one line, containing nn, mm, rbr_b, cbc_b, rdr_d, cdc_d, and pp (4nm1054 \le n \cdot m \le 10^5, n,m2n, m \ge 2, 1rb,rdn1 \le r_b, r_d \le n, 1cb,cdm1 \le c_b, c_d \le m, 1p991 \le p \le 99) — the sizes of the room, the initial position of the robot, the position of the dirt cell and the probability of cleaning in percentage.

For each test case, print a single integer — the expected time for the robot to clean the dirty cell, modulo 109+710^9 + 7.

Input

Each test contains multiple test cases. The first line contains the number of test cases tt (1t101 \le t \le 10). Description of the test cases follows.

A test case consists of only one line, containing nn, mm, rbr_b, cbc_b, rdr_d, cdc_d, and pp (4nm1054 \le n \cdot m \le 10^5, n,m2n, m \ge 2, 1rb,rdn1 \le r_b, r_d \le n, 1cb,cdm1 \le c_b, c_d \le m, 1p991 \le p \le 99) — the sizes of the room, the initial position of the robot, the position of the dirt cell and the probability of cleaning in percentage.

Output

For each test case, print a single integer — the expected time for the robot to clean the dirty cell, modulo 109+710^9 + 7.

Samples

Sample Input 1

6
2 2 1 1 2 1 25
3 3 1 2 2 2 25
10 10 1 1 10 10 75
10 10 10 10 1 1 75
5 5 1 3 2 2 10
97 98 3 5 41 43 50

Sample Output 1

3
3
15
15
332103349
99224487

Note

In the first test case, the robot has the opportunity to clean the dirty cell every second. Using the geometric distribution, we can find out that with the success rate of 25%25\%, the expected number of tries to clear the dirty cell is 10.25=4\frac 1 {0.25} = 4. But because the first moment the robot has the opportunity to clean the cell is before the robot starts moving, the answer is 33.

Illustration for the first example. The blue arc is the robot. The red star is the target dirt cell. The purple square is the initial position of the robot. Each second the robot has an opportunity to clean a row and a column, denoted by yellow stripes.

In the second test case, the board size and the position are different, but the robot still has the opportunity to clean the dirty cell every second, and it has the same probability of cleaning. Therefore the answer is the same as in the first example.

Illustration for the second example.

The third and the fourth case are almost the same. The only difference is that the position of the dirty cell and the robot are swapped. But the movements in both cases are identical, hence the same result.