#P1408B. Arrays Sum

    ID: 5550 Type: RemoteJudge 1000ms 256MiB Tried: 0 Accepted: 0 Difficulty: (None) Uploaded By: Tags>constructive algorithmsgreedymath*1400

Arrays Sum

No submission language available for this problem.

Description

You are given a non-decreasing array of non-negative integers $a_1, a_2, \ldots, a_n$. Also you are given a positive integer $k$.

You want to find $m$ non-decreasing arrays of non-negative integers $b_1, b_2, \ldots, b_m$, such that:

  • The size of $b_i$ is equal to $n$ for all $1 \leq i \leq m$.
  • For all $1 \leq j \leq n$, $a_j = b_{1, j} + b_{2, j} + \ldots + b_{m, j}$. In the other word, array $a$ is the sum of arrays $b_i$.
  • The number of different elements in the array $b_i$ is at most $k$ for all $1 \leq i \leq m$.

Find the minimum possible value of $m$, or report that there is no possible $m$.

The first line contains one integer $t$ ($1 \leq t \leq 100$): the number of test cases.

The first line of each test case contains two integers $n$, $k$ ($1 \leq n \leq 100$, $1 \leq k \leq n$).

The second line contains $n$ integers $a_1, a_2, \ldots, a_n$ ($0 \leq a_1 \leq a_2 \leq \ldots \leq a_n \leq 100$, $a_n > 0$).

For each test case print a single integer: the minimum possible value of $m$. If there is no such $m$, print $-1$.

Input

The first line contains one integer $t$ ($1 \leq t \leq 100$): the number of test cases.

The first line of each test case contains two integers $n$, $k$ ($1 \leq n \leq 100$, $1 \leq k \leq n$).

The second line contains $n$ integers $a_1, a_2, \ldots, a_n$ ($0 \leq a_1 \leq a_2 \leq \ldots \leq a_n \leq 100$, $a_n > 0$).

Output

For each test case print a single integer: the minimum possible value of $m$. If there is no such $m$, print $-1$.

Samples

6
4 1
0 0 0 1
3 1
3 3 3
11 3
0 1 2 2 3 3 3 4 4 4 4
5 3
1 2 3 4 5
9 4
2 2 3 5 7 11 13 13 17
10 7
0 1 1 2 3 3 4 5 5 6
-1
1
2
2
2
1

Note

In the first test case, there is no possible $m$, because all elements of all arrays should be equal to $0$. But in this case, it is impossible to get $a_4 = 1$ as the sum of zeros.

In the second test case, we can take $b_1 = [3, 3, 3]$. $1$ is the smallest possible value of $m$.

In the third test case, we can take $b_1 = [0, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2]$ and $b_2 = [0, 0, 1, 1, 1, 1, 1, 2, 2, 2, 2]$. It's easy to see, that $a_i = b_{1, i} + b_{2, i}$ for all $i$ and the number of different elements in $b_1$ and in $b_2$ is equal to $3$ (so it is at most $3$). It can be proven that $2$ is the smallest possible value of $m$.