1 solutions
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0
#include<bits/stdc++.h> using namespace std; int main() { int i, j, x, n, sum = 0, a[10010]; cin >> n >> x; for(i = 1; i <= n; i++) cin >> a[i]; for(i = 1; i <= n; i++) for(j = 1; j <= n-i; j++) if(a[j] > a[j+1]) swap(a[j],a[j+1]); for(i = x+1; i <= n-x; i++) sum += a[i]; cout << fixed << setprecision(1)<<(sum*1.0)/(n-x*2)<< endl; return 0; }
- 1
Information
- ID
- 810
- Time
- 1000ms
- Memory
- 64MiB
- Difficulty
- 10
- Tags
- # Submissions
- 1
- Accepted
- 1
- Uploaded By