4 solutions
-
0
``
#include <iostream> #include <stdio.h> int main() { int a[6][6]={0}; int b[6]; int x,y; for (int i = 1; i < 6; i++) { for (int j = 1; j < 6; j++) { scanf("%d", &a[i][j]); } } scanf("%d",&x); scanf("%d",&y); printf("\n"); for(int i=1;i<6;i++){ b[i]=a[x][i]; } for (int j = 1; j <6 ; ++j) { a[x][j]=a[y][j]; } for (int j = 1; j <6 ; ++j) { a[y][j]=b[j]; } for (int i = 1; i < 6; i++) { for (int j = 1; j < 6; ++j) { printf("%d ", a[i][j]); } printf("\n"); } return 0; }
Information
- ID
- 86
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 4
- Tags
- # Submissions
- 259
- Accepted
- 119
- Uploaded By