4 solutions

  • 0
    @ 2023-6-22 18:56:21
    #include <stdio.h>
    int main(){
        int a[6][6];
       int b[6][6];//临时用来交换变量的中间商
        int m,n;
        for(int i=1;i<=5;i++){
            for(int j=1;j<=5;j++){
                scanf("%d",&a[i][j]);
            }
        }
        scanf("%d%d",&n,&m);
        
        for(int j=1;j<=5;j++){
            b[n][j]=a[n][j];
            a[n][j]=a[m][j];
            a[m][j]=b[n][j];
        }
    
         for(int i=1;i<=5;i++){
            for(int j=1;j<=5;j++){
                if(j!=5)  printf("%d ",a[i][j]);
                else printf("%d",a[i][j]);
            }
            printf("\n");
        }
        
        return 0;
    }
    

    Information

    ID
    86
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    4
    Tags
    # Submissions
    259
    Accepted
    119
    Uploaded By