2 solutions
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0
//stl:int round(double x) ----->四舍五入函数 #include<bits/stdc++.h> using namespace std; int n,a,b,x; int main(){ //freopen("t.in","r",stdin); //freopen("t.out","w",stdout); cin>>n; int tmp=n; while(tmp--){ cin>>x; if(x>=60)b++; if(x>=85)a++; } double ans1=(double)b/n*100; double ans2=(double)a/n*100; cout<<round(ans1)<<"%"<<endl; cout<<round(ans2)<<"%"; return 0; }
Information
- ID
- 6482
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 3
- Tags
- # Submissions
- 102
- Accepted
- 47
- Uploaded By