10 solutions
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1
两种方法 都供上了。递归 和 用栈。
#include <iostream> #include <string> #include <stack> using namespace std; char charr[26] = { 'A','B','C','D','E','F','G','H','I','J' ,'K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z' }; void jinzhuan(int X,int M) { if (X == 0) { return;// 等于 0 进行返回 } jinzhuan(X / M, M); int temp = X % M; if (temp < 10) { cout << temp; } else { cout << charr[temp - 10]; } } int main(void) { int X, M; cin >> X >> M; /*stack<int> s; while (X != 0) { s.push(X % M); X /= M; } while (!s.empty()) { int temp = s.top(); if (temp < 10) { cout << temp; } else { cout << charr[temp - 10]; } s.pop(); }*/ jinzhuan(X, M); return 0; }
Information
- ID
- 288
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 4
- Tags
- # Submissions
- 121
- Accepted
- 55
- Uploaded By