*1900 - Problem Set - 追梦算法网

	ID	Problem Show tags Hide tags	AC / Tried	Difficulty
	856	P1488C Two Policemen special problem binary search brute force math 1900	0 / 0	(None)
	855	P1488D Problemsolving Marathon special problem binary search greedy 1900	0 / 0	(None)
	842	P1490G Old Floppy Drive binary search data structures math *1900	0 / 0	(None)
	829	P1492D Genius's Gambit bitmasks constructive algorithms greedy math *1900	0 / 0	(None)
	819	P1494C 1D Sokoban binary search dp greedy implementation two pointers *1900	0 / 0	(None)
	814	P1495B Let's Go Hiking games greedy *1900	0 / 0	(None)
	755	P1508A Binary Literature constructive algorithms greedy implementation strings two pointers *1900	0 / 0	(None)
	723	P1512F Education brute force dp greedy implementation *1900	0 / 0	(None)
	646	P1527B2 Palindrome Game (hard version) constructive algorithms games *1900	0 / 0	(None)
	545	P1543C Need for Pink Slips bitmasks brute force dfs and similar implementation math probabilities *1900	0 / 0	(None)
	540	P1545B AquaMoon and Chess combinatorics math *1900	0 / 0	(None)
	527	P1547F Array Stabilization (GCD version) binary search brute force data structures divide and conquer number theory two pointers *1900	0 / 0	(None)
	460	P1558B Up the Strip brute force dp math number theory two pointers *1900	0 / 0	(None)
	444	P1560F1 Nearest Beautiful Number (easy version) binary search bitmasks brute force constructive algorithms dfs and similar greedy *1900	0 / 0	(None)
	414	P1569D Inconvenient Pairs binary search data structures implementation sortings two pointers *1900	0 / 0	(None)
	318	P1585D Yet Another Sorting Problem data structures math *1900	0 / 0	(None)
	301	P1593D2 Half of Same brute force math number theory *1900	0 / 0	(None)
	273	P1600E Array Game games greedy two pointers *1900	0 / 0	(None)
	269	P1601B Frog Traveler data structures dfs and similar dp graphs shortest paths two pointers *1900	0 / 0	(None)
	205	P1611E2 Escape The Maze (hard version) dfs and similar dp greedy shortest paths trees *1900	0 / 0	(None)

Pick a problem randomly based on the current filter.